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What will be the output of the following code?
#include <iostream>
using namespace std;
int main() {
    int x = 5;
    auto lambda = [x]() mutable { x += 5; return x; };
    cout << lambda() << " ";
    cout << x;
    return 0;
}
  • a)
    10 5
  • b)
    10 10
  • c)
    Compiler Error
  • d)
    Undefined Behavior
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
What will be the output of the following code?#include <iostream>...
The lambda expression captures the variable x by value. The mutable keyword allows modifying the captured value without changing the original variable x.
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Community Answer
What will be the output of the following code?#include <iostream>...
Explanation:

Auto Lambda Function:
- In the given code, a lambda function is defined and stored in the 'lambda' variable.
- The lambda function captures the variable 'x' by value and is marked as mutable, allowing modifications to 'x' within the lambda function.

Output:
- The lambda function increments the value of 'x' by 5 and returns it, resulting in the output of the first cout statement as 10.
- After calling the lambda function, the value of 'x' outside the lambda function remains unchanged at 5, which is displayed by the second cout statement.
Therefore, the output of the code is: 10 5.
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